Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2012/iii/paper-78/4/c/ii/solution
Past exam of the mathematics course of the University of Cambridge 2012 iii Paper 78 4 c ii Solution by
Codex 0 Created 2026-10-03 Updated 2026-10-14
Substitution into the Tikhonov regularization series gives an explicit reconstruction for every :Equivalently the summand is . The Tikhonov stability bound makes the series converge in for every positive . It suppresses high-frequency components of unstable differentiation, rather than differentiating arbitrary noisy data pointwise.
The range of the Volterra integration operator is . On exactly these data, and the series converges to as . For arbitrary data outside that range, a finite regularized solution still exists, but a finite-norm unregularized solution need not exist. This is Spectral Tikhonov differentiation for the Volterra operator.
New to topics? Read the docs here!