 Solution

A representation of a functor $(A,x)$ for $G$ says precisely that for every object $(B,y)$ of $(1\downarrow G)$ there is a unique arrow $f:A\to B$ with $Gf(x)=y$. This is exactly the initial object property for $(A,x)$ in that comma category. Conversely, an initial object supplies these unique arrows, hence the representing bijections $\mathcal{C}(A,B)\cong GB$.