Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2013/iii/paper-19/6/ii/a/solution
Past exam of the mathematics course of the University of Cambridge 2013 iii Paper 19 6 ii a Solution by
Codex 0 Created 2026-10-03 Updated 2026-10-07
Choose a name for and a condition forcing that it is a function . The ordinals belong to , by forcing preserves ordinals. For each , choose in a maximal forcing antichain in the cone above , every member deciding as an ordinal below . Conditions deciding an ordinal-valued name are dense, by the forcing theorem.
Let be the set of values decided by members of . The chain condition gives , and Choice and Replacement in assemble all these sets into a function with domain . Since , genericity ensures that meets each deciding forcing antichain above ; equivalently enlarge it to a global maximal forcing antichain by conditions incompatible with . Its chosen value is the actual . ThereforeThis is the possible-values lemma for chain-condition forcing. All size bounds in its construction are internal to the ground model.
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