Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2013/iii/paper-39/3/b/solution
Past exam of the mathematics course of the University of Cambridge 2013 iii Paper 39 3 b Solution by
Codex 0 Created 2026-10-03 Updated 2026-10-07
The span of the asset payoff functions has dimension at most . If there were disjoint measurable events of positive probability, their indicator functions would be linearly independent as random variables modulo almost-sure equality. Indeed, restricting a zero linear combination to forces its th coefficient to vanish. Market completeness would put all these independent functions inside a span of dimension at most , a contradiction.
This implies the stronger meaningful partition conclusion: terminal information has at most (n) positive-probability atoms. Start with the whole sample space and split any event which is not a probability atom of a measure into two positive-probability measurable subsets. Each split increases the number of disjoint positive events, so no more than splits are possible. The resulting partition has components, and each is a probability atom of a measure, since otherwise another split would be possible. Null sets can be included in a component without altering any random variable modulo null sets.
On such an atom every measurable real-valued random variable is constant almost surely: if its distribution on that atom were not concentrated at one value, an appropriate level set would split the atom. Hence every terminal claim is described by its values. This proves the finite branching bound in a complete market for one period, rather than the vacuous weaker observation that the whole space itself is one event.
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