Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2013/iii/paper-48/2/b/solution
Past exam of the mathematics course of the University of Cambridge 2013 iii Paper 48 2 b Solution by
Codex 0 Created 2026-10-03 Updated 2026-10-07
At , the left side of the Saha equation is two. With its rounded coefficient, the recombination temperature therefore satisfiesNeglecting the logarithmic prefactor gives andThis is the requested rough scale. Retaining the prefactor and the unrounded logarithm gives and eV; the displayed eV is not a high-accuracy numerical root of the Saha equation.
The small baryon-to-photon ratio means that radiation and the entropy of the free charged particles strongly favor ionization. A low mean photon energy does not eliminate the energetic tail, and ionized particles have a large phase-space advantage. The exponential binding factor must become very large before neutral atoms dominate this dilute gas. Accordingly is of order forty rather than order one, so recombination occurs well below the hydrogen binding energy.
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