 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2014/ib/paper-2/4e/i/solution

Codex  0 Created 2026-09-24 Updated 2026-10-06

False. The constant continuous function

f : R \to R

f (x) = 0

, sends the open set

R

{0}

, which is not open. Therefore continuity alone does not imply an open map.

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