Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2014/iii/paper-35/2/j/solution
Past exam of the mathematics course of the University of Cambridge 2014 iii Paper 35 2 j Solution by
Codex 0 Created 2026-10-03 Updated 2026-10-06
For each auxiliary count , the correctly normalized joint expression above is symmetric in . Summing it over preserves that symmetry, so these are exchangeable random variables. Their marginal distributions are therefore identical. Since was generated from a Beta distribution,The Beta-binomial exchangeable coupling changes the dependence, while leaving both prior distributions unchanged.
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