 Solution

The complex tautological line bundle on ${\mathbb{P}}^1$ has fibre at a line $\ell \subseteq {\mathbb{C}}^2$ equal to $\ell$ itself:Define $\mathcal{O}(1)=\mathcal{O}(-1{)}^{\ast }$, $\mathcal{O}(k)=\mathcal{O}(1{)}^{\otimes k}$ for $k>0$, $\mathcal{O}(0)$ to be trivial, and $\mathcal{O}(k)=\mathcal{O}(-1{)}^{\otimes (-k)}$ for $k<0$. These are the tensor powers of the hyperplane line bundle.

On the two given charts, use the holomorphic local frames $e_0(w)=(1,w)$ and $e_1(z)=(z,1)$ of $\mathcal{O}(-1)$. The maps $([1:w],a)\mapsto ([1:w],a(1,w))$ and $([z:1],b)\mapsto ([z:1],b(z,1))$ are its trivializations. On the overlap $z=1/w$,Thus the frame-transition factor from $e_0$ to $e_1$ is $w^{-1}$, while the fibre-coordinate transition from chart 0 to chart 1 is $w$. Specifying both avoids an inverse-convention ambiguity.

For $\mathcal{O}(k)$, let $e_i^{(k)}$ be the induced frames; they satisfy $e_1^{(k)}=w^k{e}_0^{(k)}$. Identifying overlap sections using $e_0^{(k)}$, the Čech cochain groups and Čech coboundary for $k\ge 0$ areHere $\mathcal{O}(\mathbb{C})$ means entire functions in the coordinate of the corresponding chart. Global sections are $\ker \delta$, so $a(w)=w^{k}b(1/w)$, or $b(z)=z^{k}a(1/z)$. Expanding the entire function $a(w)={\sum }_{j\ge 0}{a}_j{w}^j$ shows that $b$ is holomorphic at zero exactly when $a_j=0$ for $j>k$. Thus a global section is determined by a polynomial of degree at most $k$, with basis $1,w,\dots ,w^k$ in the chart-0 frame. Therefore $\boxed{\dim H^0({\mathbb{P}}^1,\mathcal{O}(k))=k+1(k\ge 0)}$.