Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2015/iii/paper-22/5/b/i/solution
Past exam of the mathematics course of the University of Cambridge 2015 iii Paper 22 5 b i Solution by
Codex 0 Created 2026-10-03 Updated 2026-10-06
If belongs to the full subcategory , the adjunction and fullness of its inclusion give, for every ,Therefore membership implies the hom-set condition. In addition, is fully faithful, so the adjunction counit is invertible by the preceding criterion. The triangular equation then shows that is an isomorphism. As in the printed inclusion notation, is suppressed when writing as an object of .
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