Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2015/iii/paper-24/5/a/i/solution
Past exam of the mathematics course of the University of Cambridge 2015 iii Paper 24 5 a i Solution by
Codex 0 Created 2026-10-03 Updated 2026-10-06
Use the countable-condition collapseordered by reverse inclusion: an extension of a function is a stronger condition. All sizes and conditions here are computed in the ground model .
This forcing is countably closed: the union of a descending countable sequence is a countable partial function. Thus it adds no countable ordinal sequences and preserves . For each , the conditions whose domains contain are dense; for each , those whose ranges contain are dense. The union of the generic filter is therefore a surjection from onto , and .
Inaccessibility gives : every countable sequence is bounded below the regular , and the strong limit cardinal property bounds the number of sequences at each bound below . Hence . The forcing satisfies the -chain condition for forcing, so it preserves every cardinal above . This gives precisely the requested collapse and preservation. The assertion that is collapsed to concerns its new cardinality; the ordinal itself does not change.
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