Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2015/iii/paper-37/5/d/3/ii/solution
Past exam of the mathematics course of the University of Cambridge 2015 iii Paper 37 5 d 3 ii Solution by
Codex 0 Created 2026-10-03 Updated 2026-10-06
Let be the normalized target and its marginal distribution. A coordinate- kernel leaves and has the joint old-new measureThis is symmetric in the old and new state: the common remaining coordinates are fixed and the two conditional factors exchange places. Thus each coordinate kernel satisfies detailed balance. Averaging them with the fixed weights provesIntegrating out the old state proves invariance of . The common normalization cancels, so detailed balance can also be written with the unnormalized target. This establishes detailed balance of a random-scan Gibbs sampler and a reversible Markov chain. Fresh independent random choices make the update a Markov chain, as explained above; invariance is not an assertion that an arbitrarily initialized chain starts in stationarity.
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