Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2015/iii/paper-66/1/ii/solution

By spectral decomposition, the Von Neumann entropy is the Shannon entropy of the eigenvalues:
Throughout, logarithms have base two, so the Von Neumann entropy and Shannon entropy are measured in bits. The continuous convention includes zero eigenvalues.

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