 Solution

In steady flow, the Euler equations for an inviscid fluid and part (a) giveTaking the dot product with $\mathbf{u}$ yields $\mathbf{u}\cdot \nabla H=0$, because a cross product is perpendicular to its first factor. Part (b) therefore gives Bernoulli's quantity along streamlines:For rotational flow these constants can differ between streamlines, since $\mathbf{u}\times \mathbf{\omega }$ need not vanish and therefore $\nabla H$ need not be zero. Special rotational flows can still have one global constant when that cross product vanishes; the general conclusion is only constancy along individual streamlines.