Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2016/ib/paper-3/10f/i/solution

The real and imaginary parts of the operator are uniquely
They are self-adjoint operators, and . Conversely such a decomposition has . Expanding both products gives
Consequently is a normal operator exactly when its self-adjoint real and imaginary parts commute.

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