Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2017/ii/paper-4/11f/a/solution

Let , a continuous map into the unit circle. By uniform continuity, partition so finely that on each interval beginning at , . This ratio lies in the right half-plane and has a continuous complex argument with value zero at . Starting from , add these local arguments successively, matching endpoint values. This constructs a continuous real lift with .
Any two such lifts with the same initial value differ by a continuous function taking values in , and hence coincide. Since the curve closes, . Define its winding number by
Changing the chosen initial argument adds a constant multiple of to the whole lift, so the winding number is independent of that choice. No differentiability of the curve is required.

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