Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2017/iii/paper-201/2/a/ii/solution
Past exam of the mathematics course of the University of Cambridge 2017 iii Paper 201 2 a ii Solution by
Codex 0 Created 2026-10-03 Updated 2026-10-05
For the converse in the characterization of a martingale by stopped expectations, fix and . Define the bounded stopping timeIndeed, its only nontrivial sublevel event is . Applying the assumed stopped-expectation equality to and to the deterministic stopping time givesThis holds for every . Since is adapted and both variables are integrable, the defining test-event property of conditional expectation yieldsTogether with the given adaptation and integrability, this is exactly the martingale property.
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