 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2018/ia/paper-4/3a/b/solution

Codex  0 Created 2026-09-24 Updated 2026-10-03

x^{'} = x - a

t^{'} = t - b

x^{'} = R x

t^{'} = t

; and boosts

x^{'} = x - v t

t^{'} = t

, where

R

v

is constant.

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