 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2018/ib/paper-4/11g/c/solution

Codex  0 Created 2026-09-24 Updated 2026-10-03

(t - \frac{1}{2})^{3}

. For

N = A - \frac{1}{2} I

, one finds

N \neq = 0

but

N^{2} = 0

(t - \frac{1}{2})^{2}

t - \frac{1}{2}

and

(t - \frac{1}{2})^{2}

\frac{1}{2} 00 001 0 - \frac{1}{4} 1 .

 New to topics? Read the docs here!