 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2018/iii/paper-140/6/b/solution

Codex  0 Created 2026-10-03 Updated 2026-10-05

i (a) = (a, \dots, a)

. Its dual map is characterized by

⟨ π (η), a ⟩ = ⟨ η, i (a)⟩ = a \sum_{j = 1}^{n} η_{j} .

Consequently

π (η_{1}, \dots, η_{n}) = η_{1} + \dots + η_{n} .

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