Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2018/iii/paper-327/2/i/solution

The space of test functions is . A sequence converges to when all functions eventually have compact support in one compact set and every derivative converges uniformly:
A distribution is a continuous linear functional on this space of test functions. Equivalently, for each compact set , there are and a finite integer such that
The integer is permitted to depend on . The usual weak convergence of distributions is
Thus the convergence convention on the distribution space is its weak dual topology.
For the principal-value reciprocal distribution, the symmetric truncations can be written
The numerator is near zero by the mean value theorem, and the integrand vanishes for large because has compact support. For ,
Consequently the Cauchy principal value defines a distribution of order of a distribution at most one.
The function has local integrability, since , and therefore defines a distribution. For its distributional derivative, remove and use integration by parts on both remaining intervals:
The boundary term is and tends to zero. The omitted integral of tends to zero by local integrability. Hence the distributional derivative of the logarithmic modulus satisfies
Symmetric truncation is essential to this normalization of the principal-value reciprocal distribution.

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