Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2018/iii/paper-339/3/a/i/solution
Past exam of the mathematics course of the University of Cambridge 2018 iii Paper 339 3 a i Solution by
Codex 0 Created 2026-10-03 Updated 2026-10-05
First address the positivity request in part (a), which has no separate Solution heading in the stub. For , each and each coefficient is nonnegative. Their sum is therefore nonnegative, including at the endpoints:This is the elementary direction of the positive Bernstein coefficients for a strictly positive polynomial criterion; the converse developed later needs strict positivity.
For completeness, the convergence fact listed as (i) also has a short proof. If , the Bernstein polynomial is . Its mean argument is and . Given , uniform continuity of on the compact interval supplies such that whenever . By Chebyshev's inequality, uniformly in ,Letting and then proves . The two numbered items in the source are assumptions supplied for later parts, not additional exam questions; their stub sections contain these supporting derivations.
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