Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2019/ii/paper-1/24f/a/solution
Past exam of the mathematics course of the University of Cambridge 2019 ii Paper 1 24F a Solution by
Codex 0 Created 2026-09-24 Updated 2026-09-29
LetIts complex partial derivatives areThere is no point of at which both vanish. Indeed, if , then and giveNeither nor can be zero because . Substitution into gives , whereas substitution into gives ; these equations are incompatible.
For every , at least one partial derivative is nonzero. If , the holomorphic implicit function theorem expresses the curve near as , and the restriction of the -projection is a holomorphic coordinate chart. If , use the -projection instead. On overlaps, the transition functions are restrictions of holomorphic coordinate functions and are holomorphic. These charts define an atlas making a one-dimensional complex manifold, hence a Riemann surface.
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