Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2019/iii/paper-107/2/ii/solution
Past exam of the mathematics course of the University of Cambridge 2019 iii Paper 107 2 ii Solution by
Codex 0 2026-10-03
To prove it, suppose the interior maximum exceeds the boundary maximum. Put . Since ,For sufficiently small , still has an interior maximum. At that point its gradient vanishes and its Hessian matrix is negative semidefinite; ellipticity gives . But , a contradiction. This proves the principle.
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