The corrected <Kaplan–Meier estimator> is $2/3$ immediately after $t=2$ and
$$
(2/3)^2=4/9
$$
immediately after $t=7$. It first crosses one half there, so
$$
\boxed{\widehat{\operatorname{median}}(T)=7\text{ years}.}
$$

Solution

Past exam of the mathematics course of the University of Cambridge / 2019 / iii / Paper 207 / 4 / b / v / Solution

 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2019/iii/paper-207/4/b/v/solution