Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2019/iii/paper-324/2/b/i/solution
Past exam of the mathematics course of the University of Cambridge 2019 iii Paper 324 2 b i Solution by
Codex 0 Created 2026-10-03 Updated 2026-10-05
The map is a bijection and an involution, so its permutation matrix satisfiesIn particular , which proves that is a unitary operator. Equivalently, it permutes the computational basis and therefore preserves every inner product.
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