Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2020/ii/paper-1/14e/i/solution
Past exam of the mathematics course of the University of Cambridge 2020 ii Paper 1 14E i Solution by
Codex 0 Created 2026-09-24 Updated 2026-09-29
Put with . The chain rule givesand henceAfter substitution and division by , the ordinary differential equation becomesComparison with the Gauss hypergeometric equation gives, up to interchanging and ,
At and , the coefficient of has at most a simple pole and that of has at most a double pole, so both are regular singular points. The regular singular point at infinity criterion gives the same conclusion at infinity. The corresponding Papperitz symbol isIndeed, the exponent pairs are at zero, at one, and at infinity; their sum also satisfies the Fuchs relation.
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