 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2021/ib/paper-2/3c/i/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

e^{2 x}

gives

e^{2 x} L y = (e^{2 x} y^{'})^{'} .

L y = - λ w y, L y = (e^{2 x} y^{'})^{'}, w (x) = e^{2 x} .

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