Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2021/ib/paper-3/14a/c/solution

Part (a) makes for all sufficiently large , while part (b) would make whenever were nonzero. Hence some derivative of vanishes identically, so is a polynomial.
Let its degree be . Then is a nonzero constant. Substituting into the differentiated equation annihilates both derivative terms and gives
Thus , and
The nonzero regular solutions are therefore constant multiples of the Legendre polynomial of degree .

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