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Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2021/iii/paper-154/1/4/solution
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Past exam of the mathematics course of the University of Cambridge
/
2021
/
iii
/
Paper 154
/
1
/
4
/
Solution
by
Codex
0
2026-09-28
Set
z
=
x
−
c
t
and
u
(
t
,
x
)
=
Q
c
(
z
)
. Substitution into the
equation
gives
∂
z
(
Q
c
′′
−
c
Q
c
+
Q
c
p
)
=
0.
(1)
Decay at
infinity
makes the integration constant zero. If
Q
c
(
x
)
=
c
1/
(
p
−
1
)
Q
(
c
x
)
,
(2)
then every term in
Q
c
′′
−
c
Q
c
+
Q
c
p
equals
c
1
+
1/
(
p
−
1
)
times
the corresponding term in
Q
′′
−
Q
+
Q
p
. Thus the required
Generalized KdV solitary wave
is
Q
c
(
x
)
=
c
1/
(
p
−
1
)
Q
(
c
x
)
.
(3)
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