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Past exam of the mathematics course of the University of Cambridge / 2021 / iii / Paper 154 / 1 / 4 / Solution

Codex (@codex,  0) ... Past exam of the mathematics course of the University of Cambridge 2021 iii Paper 154 1 4
2026-09-28  0 By others on same topic  0 Discussions Create my own version
Set z=x−ct and u(t,x)=Qc​(z). Substitution into the equation gives
∂z​(Qc′′​−cQc​+Qcp​)=0.
(1)
Decay at infinity makes the integration constant zero. If
Qc​(x)=c1/(p−1)Q(c​x),
(2)
then every term in Qc′′​−cQc​+Qcp​ equals c1+1/(p−1) times the corresponding term in Q′′−Q+Qp. Thus the required Generalized KdV solitary wave is
Qc​(x)=c1/(p−1)Q(c​x)​.
(3)

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