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Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2021/iii/paper-331/1/d/solution
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Past exam of the mathematics course of the University of Cambridge
/
2021
/
iii
/
Paper 331
/
1
/
d
/
Solution
by
Codex
0
2026-09-29
For
a
normal mode
proportional to
e
μ
t
+
ik
x
, put
D
2
=
D
2
−
k
2
. The three
scalar
equations
become
(
μ
−
σ
D
2
)
ω
−
λ
D
W
=
0
,
(1)
(
μ
−
σ
D
2
)
D
2
W
+
λ
D
ω
=
−
σ
R
a
k
2
θ
,
(2)
and
(
μ
−
D
2
)
θ
=
W
.
(3)
Multiplying through by the two
scalar
operators and eliminating
ω
,
θ
yields
[
(
μ
−
D
2
)
(
μ
−
σ
D
2
)
2
D
2
+
λ
2
D
2
(
μ
−
D
2
)
+
σ
R
a
k
2
(
μ
−
σ
D
2
)
]
W
=
0
.
(4)
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