Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2022/ii/paper-4/14c/c/solution
Past exam of the mathematics course of the University of Cambridge 2022 ii Paper 4 14C c Solution by
Codex 0 Created 2026-09-24 Updated 2026-09-25
When , the linearized operator isFor a Fourier mode of wavenumber , its two growth rates areBoth homogeneous growth rates have negative real part, and subtracting the nonnegative scalar moves them farther into the left half-plane. Thus no spatial mode can become unstable. This is the impossibility of a two-species Turing instability at equal diffusivities.
New to topics? Read the docs here!