 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2023/ia/paper-1/3e/i/solution

Codex  0 Created 2026-09-24 Updated 2026-10-03

No. Take

f (x) = x^{2}

a = 0

, and

g (y) = ∣ y ∣

g

f (0) = 0

, but

g (f (x)) = x^{2}

is differentiable. Neither function is constant on an interval.

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