 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2023/ib/paper-2/14a/a/i/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

Regularity at the origin excludes the natural logarithm and every negative radial power. Thus

c_{0} = 0, c_{n} = d_{n} = 0 (n \geq 1) .

a_{0}, a_{n}, b_{n}

remain arbitrary.

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