Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2023/ib/paper-2/9e/a/solution

Let act by left multiplication on the set of left cosets. Every orbit has size a power of , while
is not divisible by . Therefore at least one orbit has size one. If is fixed, then for every , so , equivalently
This is Sylow containment from a coset fixed point.
The remaining Sylow theorems state that Sylow -subgroups exist, that any two are conjugate, and that their number satisfies

New to topics? Read the docs here!