 Solution

This is the ideal Diesel cycle. In the $(p,V)$ plane, $A\to B$ is an adiabatic curve running up and left, $B\to C$ is a horizontal constant-pressure segment running right, $C\to D$ is an adiabatic curve running down and right, and $D\to A$ is a vertical constant-volume segment running down. The traversal is clockwise, so the enclosed area is positive work output.

In the $(T,S)$ plane, the two reversible adiabats are vertical because entropy is constant: $A\to B$ rises at $S_A=S_B$, and $C\to D$ falls at $S_C=S_D$. Along $B\to C$, the heat increment at constant pressure issoAlong the constant-volume curve $D\to A$,which givesThus $B\to C$ runs up and right and $D\to A$ runs down and left between the two vertical adiabats.