Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2023/iii/paper-307/1/iii/solution

For
the three F-terms are
The equation forces , after which ; hence no supersymmetric vacuum exists. Minimizing over sets , leaving
The two real quadratic eigenvalues about are , so the stated hierarchy makes stable. The vacua are
This is an O'Raifeartaigh model: supersymmetry is spontaneously broken and is a classical pseudomodulus.

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