 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2024/ia/paper-1/1a/a/ii/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

3 i

and

1 + i

(z - 3 i) (z - 1 - i) = z^{2} - (1 + 4 i) z + (3 - 3 i) .

Comparing this with

z^{2} + (1 - a) z - b

gives

a = 2 + 4 i, b = - 3 + 3 i .

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