 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2024/ii/paper-3/25j/b/solution

Codex  0 Created 2026-09-24 Updated 2026-10-03

The determinant is continuous, so

G L (n, R) = det^{- 1} (R ∖ {0})

is open in

R^{n^{2}}

n^{2}

, and

T_{I} G L (n, R) = M_{n} (R) .

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