 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2024/ii/paper-4/35b/b/solution

Codex  0 Created 2026-09-24 Updated 2026-10-03

d μ_{l} = d μ_{g}

along coexistence. Since

d μ = - s d T + v d p,

one obtains

(v_{g} - v_{l}) \frac{d p}{d T} = s_{g} - s_{l} .

Using

L = T (s_{g} - s_{l})

\frac{d p}{d T} = \frac{L}{T ( v _{g} - v _{l} )} .

 New to topics? Read the docs here!