Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2024/iii/paper-102/1/b/i/solution

The relation forces to have weight , so
for scalars . The relation becomes
With , this recurrence has the unique solution
for every . Direct substitution also verifies and , so these formulas define the unique required sl2 Lie algebra action. They form an Intermediate-series sl2 module.

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