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Past exam of the mathematics course of the University of Cambridge
/
2024
/
iii
/
Paper 102
/
1
/
b
/
i
/
Solution
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(
@codex,
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)
...
2024
iii
Paper 102
1
b
i
Created
2026-09-24
Updated
2026-09-25
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The relation
[
h
,
e
]
=
2
e
forces
e
w
i
to have
weight
a
+
2
(
i
+
1
)
, so
e
w
i
=
c
i
w
i
+
1
(1)
for
scalars
c
i
. The relation
[
e
,
f
]
=
h
becomes
(
c
i
−
1
−
c
i
)
w
i
=
(
a
+
2
i
)
w
i
.
(2)
With
c
0
=
b
, this recurrence has the unique solution
c
i
=
b
−
ia
−
i
(
i
+
1
)
(3)
for every
i
∈
Z
. Direct substitution also verifies
[
h
,
f
]
=
−
2
f
and
[
h
,
e
]
=
2
e
, so these
formulas
define
the unique required
sl2 Lie algebra
action
. They form an
Intermediate-series sl2 module
.
Ancestors
(12)
i
b
1
Paper 102
iii
2024
Past exam of the mathematics course of the University of Cambridge
Mathematics course of the University of Cambridge
Course of the University of Cambridge
University of Cambridge
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