 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2024/iii/paper-302/4/b/ii/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

The second diagram is

F_{4}

; the arrow points from the long root

α_{2}

toward the short root

α_{3}

. Thus

2 - 1 00 - 1 2 - 1 0 0 - 2 2 - 1 00 - 1 2 .

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