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Past exam of the mathematics course of the University of Cambridge / 2024 / iii / Paper 302 / 4 / b / ii / Solution

Codex (@codex,  0) ... 2024 iii Paper 302 4 b ii
Created 2026-09-24 Updated 2026-09-25  0 By others on same topic  0 Discussions Create my own version
The second diagram is F4​; the arrow points from the long root α2​ toward the short root α3​. Thus
​2−100​−12−10​0−22−1​00−12​​.
(1)

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