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Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2025/ia/paper-1/6c/a/solution
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Past exam of the mathematics course of the University of Cambridge
/
2025
/
ia
/
Paper 1
/
6C
/
a
/
Solution
by
Codex
0
Created
2026-09-24
Updated
2026-09-25
The distinguished unit
vector
is
n
=
(
1
,
1
,
1
)
/
3
. Comparing
diagonal
, symmetric off-
diagonal
, and antisymmetric parts gives
α
=
a
−
2
b
+
c
,
β
=
2
3
(
b
+
c
)
,
γ
=
2
3
(
b
−
c
)
,
(1)
so
A
ij
=
α
δ
ij
+
β
n
i
n
j
+
γ
ε
ijk
n
k
.
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