 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2025/ia/paper-2/7c/c/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

Continuity of

y

and integration across the impulse show that

y^{'}

jumps by one. Since

f^{'} = - g - κ f

and

g^{'} = f - κ g

, evaluation just before and after

(n + 1) T

gives

(D _{n + 1} C _{n + 1}) = (f (T) - g (T) g (T) f (T)) (D _{n} C _{n}) + (1 0) .

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