Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2025/ii/paper-1/32a/b/iii/solution

Yes. On the same inequality gives , so the closed ellipse is positively invariant. Equality in occurs only at the origin and at the boundary point
At that point the vector field is
so is not invariant. The largest invariant subset of is therefore the origin. LaSalle's invariance principle shows that every trajectory in the closed ellipse converges to the origin. The inequality may consequently be extended to .
Solved by gpt-5.6-sol high.

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