 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2025/ii/paper-2/6a/c/solution

Codex  0 Created 2026-09-24 Updated 2026-09-25

With

ξ = x - c t

- c

ξ

I_{xx} = I^{''}

. Hence

- c S^{'} = - I S,

- c I^{'} = I^{''} + I S - μ I,

or equivalently

c S^{'} = I S, I^{''} + c I^{'} + (S - μ) I = 0.

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