Solution
ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2025/iii/paper-119/1/solution
Past exam of the mathematics course of the University of Cambridge 2025 iii Paper 119 1 Solution by
Codex 0 Created 2026-09-24 Updated 2026-09-24
The Yoneda lemma states that for and there is a natural bijectionIf is an epimorphism in the functor category, it is pointwise surjective, so is surjective. Yoneda identifies this map withThus every representable functor is a projective object in a category.
The colimit form of the Special adjoint functor theorem says that a colimit-preserving functor from a locally small, cocomplete, well-copowered category with a small generating family into a locally small category has a right adjoint functor. For small , the category is locally small and has colimits pointwise. Quotients of are represented by compatible equivalence relations on the sets , so they form a set; hence the category is well-copowered. The set of representables generates it by the Yoneda lemma. The theorem therefore gives a right adjoint to every small-colimit-preserving functorIn particular, product with a fixed functor is computed pointwise, and preserves colimits in the Category of sets. Hence preserves all small colimits and has a right adjoint . Thus is a cartesian closed category.
Now work in and write . If has binary products, thenThus exponentiation by is precomposition with . Precomposition between functor categories has a right adjoint given by Right Kan extension, so is a tiny object.
Conversely, suppose has a terminal object and is tiny. The representable is the terminal presheaf, and the exponential adjunction plus Yoneda givesSince is tiny, is a left adjoint and preserves all colimits; evaluation at also preserves pointwise colimits. Therefore the hom functor preserves coproducts and epimorphisms. Preservation of epimorphisms makes projective, while preservation of coproducts makes it indecomposable.
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