A <vector superfield> is a real <superfield>,
$$
V=V^\dagger.
$$
For a non-Abelian gauge theory it is also Lie-algebra valued, $V=V^aT_a$. The reality condition permits the component expansion to be reduced to <Wess-Zumino gauge>, where the physical fields are a gauge field and gaugino together with a real auxiliary field.

Solution

Past exam of the mathematics course of the University of Cambridge / 2025 / iii / Paper 307 / 1 / ii / Solution

 Solution

ID: past-exam-of-the-mathematics-course-of-the-university-of-cambridge/2025/iii/paper-307/1/ii/solution